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Techno Linear Motion Catalog 33 Technical Information where: w    = weight (lb) p = pitch (threads per inch) I(eq)  = equivalent polar inertia (lb in2) to calculate lead screw inertia (steel screw) I(screw) = D4 x length x .028 Example: Weight = 1000 lbs Velocity = 0.15 feet per second Time to Reach Velocity = 0.1 seconds Ball Screw Diameter = 1.5" Ball Screw Length = 48" Ball Screw Pitch = 5 threads per inch Motor Rotor Inertia = 2.5 lb • in2 Friction Force to Slide Weight = 6 oz 1 I(eq) = w x –– x .025 = 1000 x ––– x .025 = 1.0 lb • in2 I(screw) = D4 x length x .028 = 5.06 x 48 x .028 = 6.8 lb in2 I(rotor) =   2.5 lb in2    ––––––––––––––––––––––––––––––––––––––––– I(total) = 10.3 lb in2 Velocity is 0.15 feet per second, which is equal to 1800 steps per second (motor steps in 1.8° increments). Torque to accelerate system:   '      p x 1.8 1800     3.1416 x 1.8 T = 2 x IO x ––– x –––––––– x ––– = 2 x 10.3 x ––––– x –––––––––––– x ––– = 484 oz in   t          180 180            24 Torque to overcome friction: F = .393 x T x p x eff. –––– F T = ––––––––––––– = ––––––––––––– = 0.22 ozin       .393 x p x eff. where: F = frictional force (lb) T = torque (ozin) p = lead screw pitch (threads per inch) Total torque required = 0.22 oz • in + 484.00 oz in = 484.22 oz in After determining the required motor size, it is recommended to add a 20% factor of safety so that unexpected dynamic loads are easily handled by the motor. Sizing Servo Motors:   Two  separate  torque  figures  are  needed  when  selecting  a  DC  motor  —  a  peak torque, being the sum of acceleration and friction torques, and a continuous torque, which is the friction component only.  The torque produced by the motor is given by: T = Kt I + = p2 25 1 + 16 6 1 1 24 0.1 .393 x 5 x 0.90